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# What is the empirical formula of the compound? Topic: What is the empirical formula of the compound?
September 20, 2019 / By Alisha
Question: When a 0.860 g sample of an organic compound containing C, H, and O was burned completely in oxygen, 1.64 g of CO2 and 1.01 g of H2O were produced. What is the empirical formula of the compound? ## Best Answers: What is the empirical formula of the compound? Uni | 7 days ago
combustion reaction occurs as follows organic compound + O2 --> H2O + CO2 therefore, you need to eleminate the oxygen mass from CO2 and H2O and then calculate the ratios. The reason for this is because the oxygen in H2O and CO2 is not entirely from the compound, but also from combustion O2 to approach this problem, we need to calculate the number of moles of each element in the compound and then figure out their ratio moles of CO2 = mass / molar mass = 1.64g / 44.01g/mol = 0.0372moles one mole CO2 contains one mole carbon moles carbon = (0.0372mol) * 1 = 0.0372........ (1) mass carbon in sample = mass CO2 - mass O = 1.64g - 1.19g = 0.45g repeat the same process for hydrogen in H2O moles H2O = mass / molar mass = 1.01g / 18.0g/mole = 0.0561moles one mole H2O contains two moles hydrogen atoms moles H in sample = 2 * (0.0561moles) = 0.112moles..... (2) mass of oxygen in sample = mass sample - (mass C + mass H) = mass sample - (molar mass*#moles C + molar mass*#moles H) = 0.860g - (12.0*0.0372 + 1.00*0.112) = 0.122g number of moles of O in sample = mass / molar mass = 0.122g / 16.0g/mol = 0.00762moles..... (3) moles C : moles H : moles O 0.0372 : 0.112 : 0.00762 3.72 : 1.12 : 0.762 approximately: 10 : 3 : 2 empirical formula C10H3O2
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Did you like the answer? What is the empirical formula of the compound? Share with your friends Originally Answered: What does an organic compound contain?.HELP PLEASE?
An organic compound is any member of a large class of chemical compounds whose molecules contain carbon and hydrogen; therefore, carbides, carbonates, carbon oxides and elementary carbon are not organic (see below for more on the definition controversy for this word). The study of organic compounds is termed organic chemistry, and since it is a vast collection of chemicals (over half of all known chemical compounds), systems have been devised to classify organic compounds. A few of the compound classes based on the functional groups they carry are as follows: Acid anhydrides Acyl halides Alcohols Aldehydes Alkanes Alkenes Amides Amines Aromatics Azo compounds Carboxylic acids Esters Ethers Haloalkanes Imines Ketones Nitriles Nitro compounds Organometallic compounds Phenols Polymers, including all plastics Thiols many organic compounds are also of prime importance in biochemistry: Many organic compounds are also of prime importance in biochemistry: Antigens Polysaccharides, carbohydrates and sugars Enzymes Hormones Lipids and fatty acids Neurotransmitters Nucleic acids Proteins, peptides and amino acids Vitamins Are enough?Vitamins ,Proteins, peptides and amino acids ,Enzymes ,Hormones ,Lipids and fatty acids ......... Originally Answered: What does an organic compound contain?.HELP PLEASE?
Homework, isn't it? Organic compounds consist basically of carbon and hidrogen links that encase other atomic elements, giving way to molecules much more complex and bigger than those of inorganic componds. The're called 'organic' because they require to exist of induced energy only available in living things; chemical processes alone can't generate such complex substances. One of these are the amoino-acids that constitute your DNA. Ritchie
This is a logical procedure based on the following assumptions: all of the C in the CO2 came from the original sample, and all of the H in the H2O came from the original sample. The difference in mass that these account for is due to the O in the original sample. First calculate the number of moles of CO2 in 1.64g. This is also the number of moles of C in the original sample. Now do the same calculation for H2O in 1.01g. This is the number of moles of H in the original sample. Now use the at wt of C and of H to determine the weight of O and of H in the original sample. The difference is the weight due to O in the original sample. Use the at wt of O to determine how many moles that is. You now have the relative molar proportions of C, H, and O in the original sample. To determine the empirical formula, pick the element representing the lowest molar quantity, and divide each one by that number and finish up by rounding these relative values to their nearest whole number ratios.
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An empirical formulation shows a chemical equation utilising the smallest entire form ratios. that's no longer in many circumstances the surely chemical equation. in case you determine the atomic mass of the empirical formulation and the atomic mass of the compound that's ordinary to locate the molecular formulation. If the empirical formulation is C2H5 all of us know the burden of that's 17amu. If all of us know the the compound has an atomic mass of fifty 8, then we are able to divide fifty 8 by potential of the empirical amu, which might bypass away us with 2. this suggests we ought to multiply the empirical formulation by potential of two to get the molecular formulation. subsequently the molecular formulation would be C4H10. you could verify the respond by potential of determining the molecular weight of this compound.
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